[ncl-talk] Some operation questions about list in NCL

[Will Hobbs]

Lucky

You can index an element within an array that is part of a  list in exactly the same way that you can index a standalone array – just think of lista[2] as the array ‘c’. In your example:

>print( c(1) )   ;returns “two”

>print( lista[2](1) )   ;also returns “two”

From: ncl-talk <ncl-talk-bounces at ucar.edu> on behalf of 半个丑角 <644457443 at qq.com>
Date: Thursday, 7 March 2019 at 2:10 PM
To: ncl-talk <ncl-talk at ucar.edu>
Subject: [ncl-talk] Some operation questions about list in NCL

Dear NCL team or users,
      Hello, every body! It's kind for you all to read my letter!
      It was known that NCL have a data struction called list, into which we can store different types of data together. But I got confused about its operation to get an exact data from a list. To make my question more clearly, set the following codes as an example:

> begin
> a = (/1,2,3/)
> b = (/3,4,5,6,7/)
> c = (/"one","two"/)
> lista = [/a,b,c/]
> print(lista[2])
> end

As a result, in the screen, it will be:

> Variable: c
> Type: string
> Total Size: 8 bytes
>                 2 values
> Number of Dimensions: 1
> Dimensions and sizes:   [2]
> Coordinates:
> (0)     one
> (1)     two
     My question is that, list[2] will get the third array in the list, but how can I get the elements in the third array one by one? how can I index "two" in my ncl script when I need to read it out?
     I feel sorry to disturb you, but I do need a help. Again, thanks for reading my letter!

Cheers,
Lucky


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