[ncl-talk] regression with lag
Kevin Hallock
hallock at ucar.edu
Mon Oct 2 17:44:33 MDT 2017
Hi,
I noticed in your code’s do-loop that you’re incrementing n independently of the loop.
If you modify the loop to include “print(n)”:
do n=0,nlagr-1
n = n+1
print(n)
Regdata(:,:,n) =regline(x(0:Nend-n-yLag), P1(:,:,yLag+n:Nend))
end do ;
you can see that the only values of “n” used in the “Regdata(:,:,n) =…” line are (/1,3,5,7,9,11,13,15,17,19,21/), because n is being incremented by both the loop structure itself and the “n = n+1” line.
If this is intentional and you want your value of n to increase by 2 every loop iteration, you could cleanly write this by adding a third comma-separated value on the “do n=“ line, for example:
do n=0,nlagr-1,2
print(n)
end do
Otherwise, you might want to try removing the “n = n+1” line and rerunning your script.
Regarding the subscript error you experienced, I believe that the final 21 value mentioned above is causing the error you’re seeing, as the third dimension of Regdata is “nlagr” elements long — 21 in this case, with valid indices ranging from 0 to 20, inclusive.
I hope this helps,
Kevin
> On Oct 2, 2017, at 8:25 AM, Sancta Vega <sanctavega at gmail.com> wrote:
>
> according to this answer https://www.ncl.ucar.edu/Support/talk_archives/2013/2968.html <https://www.ncl.ucar.edu/Support/talk_archives/2013/2968.html>
>
> I need the 10 positive and negative lag regression of my data x(time), P1(lat,lon,time) but I dont loop trough lat lon .
>
> This is my code :
>
> dim_s = dimsizes(P1) ;;;
> Nend = 5000 ; length of x
> nlagr= 21 ; +- 10 lag
> yLag = 10
>
> Regdata = new((/dim_s(0),dim_s(1),nlagr/),"float")
>
> n=-1
> do n=0,nlagr-1
> n= n+1
> Regdata(:,:,n) =regline(x(0:Nend-n-yLag), P1(:,:,yLag+n:Nend))
> end do ;
>
>
> This give me an error :
> fatal:Subscript out of range, error in subscript #2
> fatal:An error occurred reading P1
>
> I try to replace regline by regCoef and get the same error message.
>
> Thanks in advance!!
>
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