[ncl-talk] first index in the sequence,

Sat May 6 07:25:48 MDT 2017

Hi Xi,

I think you want to do something like

> x=(/2.1, 3.2, 4.3, -999, -999, 7.6, 8.7, 9.8/)
> x at _FillValue=-999

first_index = x(0)
print(x(0))

Bye,
Karin

> Am 05.05.2017 um 17:48 schrieb Xi Chang <xi.chang01 at gmail.com>:
> 
> Dear NCL,
> 
> Could you suggest me how to get the first index in the sequence?
> for instance:
> 
> x=(/2.1, 3.2, 4.3, -999, -999, 7.6, 8.7, 9.8/)
> x at _FillValue=-999
> 
> the first index in the sequence will be
> (0) 2.1 and
> (5) 7.6
> 
> I do appreaciate for your help.
> 
> Best,
> Xi
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