[ncl-talk] How to find the same elements in two matrixes
Yong-jie Huang
huangyj at mail.iap.ac.cn
Fri Dec 19 18:50:00 MST 2014
Hi, I think that you can just do:
ncl 0> A = (/ 1, 2, 3, 4, 5, 6, 7, 8, 9/)
ncl 1> B = (/ 2, 14, 7, 1/)
ncl 2>
ncl 3> C = A(ind(.not.ismissing(get1Dindex(B,A))))
ncl 4> print(C)
Variable: C
Type: integer
Total Size: 12 bytes
3 values
Number of Dimensions: 1
Dimensions and sizes: [3]
Coordinates:
(0) 1
(1) 2
(2) 7
Good luck!
Yongjie Huang
> Date: Fri, 19 Dec 2014 08:39:55 -0700
> From: Dennis Shea <shea at ucar.edu>
> Subject: Re: [ncl-talk] How to find the same elements in two matrixes
> To: Lin Wang <wanglin at post.iap.ac.cn>
> Cc: ncl-talk <ncl-talk at ucar.edu>
> Message-ID:
> <CAOF1d_5DLMe=Tv794H9ekb598XgNKcuf9AtES=9X8ABhj9pFWg at mail.gmail.com>
> Content-Type: text/plain; charset="utf-8"
>
> I do not think you can do it without a loop.
>
> function get_dup_elements(a[*], b[*])
> begin
> dima = dimsizes(a)
> dimb = dimsizes(b)
> ndup = -1
>
> if (dima.le.dimb) then
> dimd = new( dima, typeof(a))
> do n=0,dima-1
> ii := ind(b.eq.a(n))
> if (.not.ismissing(ii(0))) then
> ndup = ndup+1
> dimd(ndup) = a(n)
> end if
> end do
> else
> dimd = new( dimb, typeof(a))
> do n=0,dimb-1
> ii := ind(a.eq.b(n))
> if (.not.ismissing(ii(0))) then
> ndup = ndup+1
> dimd(ndup) = b(n)
> end if
> end do
>
> end if
>
> return(dimd(0:ndup))
> end
>
> A = (/ 1, 2, 3, 4, 5, 6, 7, 8, 9/)
> B = (/ 2, 14, 7, 1/)
>
> dup = get_dup_elements(A,B)
> print(dup)
>
> ;; sort(dup) ; ascending order
>
>
>
>
> On Wed, Dec 17, 2014 at 1:59 AM, Lin Wang <wanglin at post.iap.ac.cn> wrote:
>
> > Dear all,
> >
> > Suppose:
> > A = (/ 1, 2, 3, 4, 5, 6, 7, 8, 9/)
> > B = (/ 2, 14, 7, 1/)
> >
> > If don't use loop, how to find the same elements between A and B such as
> > (/1, 2, 7/)? Thanks.
> >
> > Best wishes,
> > Lin Wang
> >
-----------------------------------------------------------------------------------
HUANG Yong-jie
Key Laboratory of Cloud-Precipitation Physics and Severe Storms (LACS),
Institute of Atmospheric Physics, Chinese Academy of Sciences
Email Address: huangyj at mail.iap.ac.cn OR huangynj at gmail.com
-----------------------------------------------------------------------------------
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