[ncl-talk] error: fatal:The result of the conditional expression yields a missing value. NCL can not determine branch, see ismissing function
Dennis Shea
shea at ucar.edu
Fri Aug 22 20:43:47 MDT 2014
MN is correct ... maybe you do't have any values less than 0.0
do j=0,173
indices=ind(data1(j,:).lt.0.)
if (.not.ismissing(indices(0))) then
first=indices(0)
if(first.gt.121) then
date(j)=(first-121)+365
else
date(j)=first+244
end if
delete(first)
end if
delete(indices)
end do
===
If you have a recent version of NCL, you could use the
reassignment operator :=
This will eliminate the need for 'delete'
do j=0,173
indices := ind(data1(j,:).lt.0.)
if (.not.ismissing(indices(0))) then
first := indices(0)
if(first.gt.121) then
date(j)=(first-121)+365
else
date(j)=first+244
end if
end if
end do
On Fri, Aug 22, 2014 at 3:22 PM, Xi Chang <xi.chang01 at gmail.com> wrote:
> so that in the end, i would have only as *date(station) * contain the
> index pointed to first date having negative value..
>
>
> On Sat, Aug 23, 2014 at 6:21 AM, Xi Chang <xi.chang01 at gmail.com> wrote:
>
>> I checked,, they are ok,, Im just afradi that the problem is here
>>
>> ...
>> * delete(indices)*
>> * delete(first)*
>> end do
>>
>> I delete them, so the the return value can not be loaded when i=1->173,
>> as they are deleted when i=0.
>> do you have any suggestion,, i just want to save every first date which
>> has negative value from my 2D data (station, time).
>>
>> Thank you
>>
>>
>>
>>
>> On Sat, Aug 23, 2014 at 6:12 AM, Michael Notaro <mnotaro at wisc.edu> wrote:
>>
>>> Perhaps sometimes you never have a negative data value. Then indices
>>> would be empty.Try printing indices each time in the 0,173 loop to check.
>>>
>>>
>>> On 08/22/14, Xi Chang wrote:
>>> > Thanks NCL and Michael,
>>> >
>>> > Do you know the source of this following error: fatal:The result of
>>> the conditional expression yields a missing value. NCL can not determine
>>> branch, see ismissing function
>>> >
>>> >
>>> > do j=0,173
>>> > indices=ind(data1(j,:).lt.0.)
>>> > first=indices(0)
>>> > if(first.gt.121) then
>>> > date(j)=(first-121)+365
>>> > else
>>> > date(j)=first+244
>>> > end if
>>> > delete(indices)
>>> > delete(first)
>>> > end do
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> > On Fri, Aug 22, 2014 at 5:40 AM, Michael Notaro <mnotaro at wisc.edu(javascript:main.compose()>
>>> wrote:
>>> >
>>> > > I think this should work.
>>> > >
>>> > >
>>> > > Say, the daily time series is x(0:364).
>>> > >
>>> > > indices=ind(x.lt.0.)
>>> > > first=indices(0)
>>> > >
>>> > >
>>> > >
>>> > >
>>> > > On 08/21/14, Xi Chang wrote:
>>> > > > Hallo NCL people,
>>> > > >
>>> > >
>>> > > > I have a question, i have a daily data 1D (point),, i'd like
>>> to get the index which has the first negative value and save the index per
>>> year. if i have 20 years, then i'll have 20 indices which are
>>> associated with first negative value each year.
>>> > > >
>>> > > >
>>> > > > Thank you.
>>> > >
>>>
>>
>>
>
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