[ncl-talk] Coordinate variables must be the same dimension as their dimension

[Mary Haley]

You are reading lat and lon off *all* files, which I don't think is what
you want.

If your lat/lon are the same across all files, then instead of doing this:

        lat = f[:]->lat
        lon = f[:]->lon

Try this:

        lat = f[0]->lat
        lon = f[0]->lon

This will read lat/lon off the first file in the list.

Really, though, since you are reading u and v, and since they have lat/lon
coordinate arrays attached to them, you can just use those, instead of
reading lat/lon separately. For example:

        wind_dir&lat = u&lat
        wind_dir&lon = u&lon

--Mary


On Fri, Mar 4, 2016 at 4:00 PM, Amadou Coulibaly <mpapin24 at gmail.com> wrote:

> Dear NCL users,
>
> I am getting some errors messages that I don't understand them. I am using
> wind speed/direction from CFSR data to do a plot, but below are errors
> occurring:
>
> fatal:Coordinate variables must be the same dimension as their dimension
> fatal:No coordinate variable exists for dimension (lat) in variable
> (wind_dir)
> fatal:["Execute.c":8578]:Execute: Error occurred at or near line 59 in
> file monthly_lsb_test2.ncl
>
> So I tried to print out lat/lon and u:
> Variable: lon
> Type: float
> Total Size: 15840 bytes
>             3960 values
> Number of Dimensions: 1
> Dimensions and sizes:    [lon | 3960]
> Coordinates:
>             lon: [-5.. 5]
> Number Of Attributes: 4
>   name :    lon
>   long_name :    longitude
>   units :    degree_east
>   valid_range :    ( -5,  5 )
>
> Variable: lat
> Type: float
> Total Size: 9120 bytes
>             2280 values
> Number of Dimensions: 1
> Dimensions and sizes:    [lat | 2280]
> Coordinates:
>             lat: [8.8985..3.2784]
> Number Of Attributes: 4
>   name :    lat
>   long_name :    latitude
>   units :    degree_north
>   valid_range :    ( 3.2784, 8.8985 )
>
> Variable: u
> Type: float
> Total Size: 36636864 bytes
>             9159216 values
> Number of Dimensions: 3
> Dimensions and sizes:    [time | 14608] x [lat | 19] x [lon | 33]
> Coordinates:
>             time: [ 1..87643]
>             lat: [8.8985..3.2784]
>             lon: [-5.. 5]
> Number Of Attributes: 5
>   standard_name :    eastward_wind
>   product_description :    1-hour Forecast
>   units :    m s-1
>   level :    Specified height above ground - value: 10 m
>   _FillValue :    3.4e+38
>
> I realized that the dimension sizes of lat/lon are different in u. I have [lat
> | 2280], [lon | 3960], but in u I have [time | 14608] x [lat | 19] x [lon
> | 33].
>
> What is wrong with my code? Please find attached my script
>
> Best
>
> --
> * COULIBALY   AMADOU   *
> PhD  Student  on  West  African  Climate  System (WACS)
> FUTA - Federal  University  of  Technology of Akure, Nigeria
>
> *Visiting Student - *
> *University of Cologne, Germany**Institute of Geophysics and Meteorology*
> Pohligstr. 3 / Office 3.102
> D-50969 Köln
>
> *Project*: WASCAL (West African Science Service Centre on Climate Change
> and Adapted Land Use)
> Phone:(+234) 812 965 3659 /(+223) 90 08 26 71 /(+226) 64 57 37 27 /+49
> 15218352574
>
> E-mail: mpapin24 at gmail.com / coulibalya68 at yahoo.com
>
> "*The time is always right to do right": Nelson Mandela*
>
> *"Character is like a tree and reputation like a shadow.  The shadow is
> what we think of it; the tree is the real thing" : Abraham Lincoln*
>
> *"Do what you can, with what you have, where you are" Theodore Roosevelt*
>
>
>
>
>
>
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