[pyngl-talk] contour path coordinates from Ngl.contour
Fearon, Dr. Matthew, Contractor, Code 7533
matthew.fearon.ctr at nrlmry.navy.mil
Wed Dec 23 16:07:43 MST 2020
Hi,
I sent this question to pyngl-talk a while back, please see below. Thought
I'd try again. If anyone has any advice that would be great.
Thank you,
Matt
From: pyngl-talk <pyngl-talk-bounces at ucar.edu> On Behalf Of Fearon, Dr.
Matthew, Contractor, Code 7533 via pyngl-talk
Sent: Wednesday, December 4, 2019 11:07 AM
To: 'pyngl-talk at ucar.edu' <pyngl-talk at ucar.edu>
Subject: [pyngl-talk] contour path coordinates from Ngl.contour
Hi,
I was wondering if anyone has experience extracting the line path/segment
coordinates that define a 2D contour field? I am interested in capturing the
coordinates of the closed or open contour paths and then defining them as
polygons. I have been successful in doing this with matplotlib, shapely,
and collections python modules, but I'd prefer the plotting functionality
and graphical look of pyngl. And in my experience, having matplotlib and
pyngl installed together has always given me problems with dependencies (at
least in the anaconda environment). Below is an example of capturing contour
path coordinates for a single value of 250 for the 2D variable vflx. I was
curious if it is possible to do something similar with Ngl.contour as I do
with matplotlib.plt.contour ? I have not figured out a way to pull the x/y
coordinates from Ngl.contour that define the contours.
Thanks for the help,
Matt
clevels=[250.]
cn = plt.contour(lon2d,lat2d,vflx, levels=clevels) #is it possible
to do this with Ngl.contour ?
#loop over the number of contour levels in cn
for i in cn.collections:
#loop over all contours per level
for contour_path in i.get_paths():
#each enumerate gives the coordinates that defines the
contour exterior
#to_polygons() closes the contour
for ncpts,cpts in enumerate(contour_path.to_polygons()):
try:
x = cpts[:,0]
y = cpts[:,1]
except:
x=[]
y=[]
for i, (lon,lat) in enumerate(cpts):
x.append(lon)
y.append(lat)
#create shapely Polygon with x and y
poly = Polygon([(k[0], k[1]) for k in zip(x,y)])
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