[ncl-talk] Filtering dates of a netcdf file (include number of gridpoints as additional criteria)
Rashed Mahmood
rashidcomsis at gmail.com
Mon Sep 9 12:14:59 MDT 2019
I think your condition (b) would be the only condition that is needed,
since if condition b is true then condition "a" must be true. So, it
appears that you do not need condition "a".
For example, if 80% of grid points for a given time and region has
precipitation values greater than zero, then for that particular time and
region area average value will always be above zero.
So I modified your script (see attached) and added a loop to find out those
time steps:
; condition b:
dims = dimsizes(rain_region)
ntime = dims(0)
tot_point = dims(1)*dims(2)*1.
ids_valid = new(ntime,integer)
req_perc = 80. ; 40.
do n=0,ntime-1
tmp_rain = rain_region(n,:,:)
oneD = ndtooned(tmp_rain)
npnts = 1.*dimsizes(ind(oneD.gt.0))
perc = 100.*(npnts/tot_point)
if(perc.gt.req_perc)then
ids_valid(n) = n
else
print(n+ " ... pertange of grid points is less than 80% = > "+perc)
end if
delete([/tmp_rain,oneD,npnts,perc/])
end do
if(.not.all(ismissing(ids_valid)))then
n_thres = ids_valid(ind(.not.ismissing(ids_valid)))
else
print(" No valid time step for the specified condition: Exiting")
exit
end if
You need to play with the variable req_perc = 80., by changing to lower
values such 40. or anything else to see how it works. In your data file no
time step would satisfy the 80% condition.
hope that helps.
On Mon, Sep 9, 2019 at 9:20 AM Lyndz <olagueralyndonmark429 at gmail.com>
wrote:
> Hi,
>
> This includes all time steps. But, in the file that I sent, I want to *count
> the number of gridpoints in each time step* with rainfall above 0. I have
> to include this in the time filter. Specifically, these two conditions: the
> area averaged rainfall is > 0 *and* at least 80% of the total gridpoints
> have rainfall > 0.
>
> Over the region I specified (rain_region), it has 40 x 30 x 10 (ntim x
> nlat x nlon).
> The above command you gave results to 5830.
> I can get a similar result by just doing this: a = num(rain_region.gt.0)
>
> Sincerely,
>
>
> On Tue, Sep 10, 2019 at 12:02 AM Rashed Mahmood <rashidcomsis at gmail.com>
> wrote:
>
>> Yes, there can be several ways of counting grid points with rainfall
>> above 0:
>>
>> e.g. say your variable name is "precp"
>>
>> oneD = ndtooned(precip)
>>
>> nVal = dimsizes(ind(oneD.gt.0))
>>
>> nVal is the number of time precip is greater than 0. Does this makes
>> sense, let me know if does not.
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>> On Mon, Sep 9, 2019 at 11:36 AM Lyndz via ncl-talk <ncl-talk at ucar.edu>
>> wrote:
>>
>>> Dear NCL experts,
>>>
>>> I would like to filter the dates in a NetCDF file when the following
>>> conditions are met:
>>> (a) Area averaged rainfall is greater than 0.
>>>
>>> Area:
>>> latS = 12.5
>>> latN = 20.0
>>> lonL = 120.0
>>> lonR = 122.5
>>>
>>> (b) At least 80% of the grid points within the specified area satisfies
>>> (a).
>>>
>>> Attached in this email is the script that I am currently working on.
>>> The sample data can be accessed here:
>>> https://www.dropbox.com/s/spfnwb4rhwjo90o/aphro_1979_AMJ.nc?dl=0
>>>
>>>
>>> *[Problem]*
>>> I was able to do the condition (a) but is there a way to count the
>>> number of grid points with rainfall above 0 over the specified region? How
>>> can I add this as another condition for the date filter?
>>>
>>> The time filter is like this:
>>>
>>> rain_threshold = 0
>>> rain_aave=wgt_areaave_Wrap(rain_region,1.0,1.0,0)
>>> printVarSummary(rain_aave)
>>> n_thres = ind(rain_aave .gt. rain_threshold) ;time indices
>>> print(n_thres)
>>> print("=====")
>>>
>>> I'll appreciate any guidance about this.
>>>
>>> Sincerely,
>>> Lyndz
>>>
>>>
>>>
>>> _______________________________________________
>>> ncl-talk mailing list
>>> ncl-talk at ucar.edu
>>> List instructions, subscriber options, unsubscribe:
>>> http://mailman.ucar.edu/mailman/listinfo/ncl-talk
>>
>>
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