[ncl-talk] Computing Aspect
Dennis Shea
shea at ucar.edu
Tue Mar 13 22:51:56 MDT 2018
Hi Mike,
Maybe a minus sign in the 2nd argument of atan2?
Given your:
; a b c
; d e f
; g h i
dzdx = ( (c + 2*f + i) - (a + 2*d + g))/dx
----
dzdy = ( (a + 2*b + c) - (g + 2*h + i))/dy
or, maybe, not sure of sign convention
dzdy = ( (g + 2*h + i) - (a + 2*b + c))/dy
----
Your code may need a minus sign before the 2nd argument:
aspect = 57.29578*atan2(dzdy,-dzdx) ; <=== minus sign ???
if (aspect.lt.0) then
aspect = 90 - aspect
end if
------------------
if (aspect(jj,ii).le.0.) then
aspect(jj,ii)=90.-aspect(jj,ii)
end if
--
If you use a minus sign, maybe you do not need other 'if' blocks?
On Mon, Mar 12, 2018 at 3:27 PM, Michael Notaro <mnotaro at wisc.edu> wrote:
> I used the following to compute terrain aspect based
>
> on elevation. But it seems the values are possibly not
>
> quite right, since they disagree with another aspect
>
> dataset I have. Does anyone see something wrong below?
>
> Michael
>
>
> ny=dims(0)
>
> nx=dims(1)
>
> aspect=new((/ny,nx/),"float")
>
> aspect at _FillValue=-999.
>
> aspect=-999.
>
>
> ; a b c
>
> ; d e f
>
> ; g h i
>
>
> do ii=1,nx-2
>
> do jj=1,ny-2
>
> if (.not.ismissing(elev(jj,ii))) then
>
> a=elevation(jj+1,ii-1)
>
> b=elevation(jj+1,ii)
>
> c=elevation(jj+1,ii+1)
>
> d=elevation(jj,ii-1)
>
> e=elevation(jj,ii)
>
> f=elevation(jj,ii+1)
>
> g=elevation(jj-1,ii-1)
>
> h=elevation(jj-1,ii)
>
> i=elevation(jj-1,ii+1)
>
> dzdx=((a+2.*d+g)-(c+2.*f+i))/(8.*800.) ; 800 m PRISM
>
> dzdy=((g+2.*h+i)-(a+2.*b+c))/(8.*800.)
>
> aspect(jj,ii)=57.29578*atan2(dzdy,dzdx)
>
> if (aspect(jj,ii).le.0.) then
>
> aspect(jj,ii)=90.-aspect(jj,ii)
>
> else if (aspect(jj,ii).gt.90.) then
>
> aspect(jj,ii)=360.-aspect(jj,ii)+90.
>
> else
>
> aspect(jj,ii)=90.-aspect(jj,ii)
>
> end if
>
> end if
>
> end if
>
> end do
>
> end do
>
>
> Michael Notaro
> Associate Director
> Nelson Institute Center for Climatic Research
> University of Wisconsin-Madison
> Phone: (608) 261-1503
> Email: mnotaro at wisc.edu
>
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