[ncl-talk] Running average

[Soma Roy]

Hello,

I used the example 2 from the below link;
https://www.ncl.ucar.edu/Document/Functions/Built-in/runave_n.shtml

But there is no change in output time dimension.
I used 365 days data over nlat x nlon as input.

I set nave=5 with expectation to get nlat x nlon for 73 times in output.

But there is no change in output dimensions. Then how to extract 5 days
running avg. over 365 days dataset?

Kindly inform me.

Thanking you,
Soma

On Mon, Dec 3, 2018, 21:10 Soma Roy <somaroy892 at gmail.com wrote:

> Thanks for the hints
>
> Soma
>
> On Mon, Dec 3, 2018, 19:21 Appo derbetini <appopson4 at gmail.com wrote:
>
>> Hi,
>> I think that you easily do it with
>> *https://www.ncl.ucar.edu/Document/Functions/Built-in/runave_n.shtml
>> <https://www.ncl.ucar.edu/Document/Functions/Built-in/runave_n.shtml>*
>>
>> Regards
>>
>> Le lun. 3 déc. 2018 à 10:54, Soma Roy <somaroy892 at gmail.com> a écrit :
>>
>>> Thank you.
>>> Efficient way to do.
>>>
>>> But I would like to know also the steps for this by using ncl.
>>>
>>> Thanks,
>>> Soma
>>>
>>> On Mon, Dec 3, 2018, 15:14 Oluwaseun Ilori <wilseun at gmail.com wrote:
>>>
>>>> Cdo will do it easily and better
>>>>
>>>> cdo -timselmean,5 infile outfile
>>>>
>>>>
>>>> On Mon, Dec 3, 2018, 10:36 AM Soma Roy <somaroy892 at gmail.com wrote:
>>>>
>>>>> Hello,
>>>>>
>>>>> I am using daily gridded rainfall datasets.
>>>>> I want to compute 5 days and 7 days running avg. of rainfall from the
>>>>> datasets over each grid points.
>>>>>
>>>>> Structure of the input file is like below;
>>>>>
>>>>> Rain (730, 129, 135)  ; (time (365*2), lat, lon)
>>>>>
>>>>> Please kindly inform me which function should I use in this case.
>>>>>
>>>>> Thanking you,
>>>>> Soma
>>>>>
>>>>>
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