[ncl-talk] Computing max of monthly NO2 data each year
Alan Brammer
abrammer at albany.edu
Tue Sep 29 13:18:49 MDT 2015
Looks like You got things sorted with Jack pretty well.
I went through and cleaned up your code a little, to make it a little more
concise in my opinion. Functionally it will be the same, but if you go
through and understand my changes here it may help you in the future.
f1 = "Europe_bis_ncl.txt"
EU = readAsciiTable(f1,7,"float",1)
EU at _FillValue = -9999
EU!0 = "time"
EU!1 = "variable"
;; if the dimeensions are named they can be reordered very easily.
;************************************************
; to plot multiple lines, you must put them into
; a mulidimensional array
;************************************************
nraw = 8
ncol = 276
nmax = ncol/12
EU_plot = new((/nraw,ncol/),float, EU at _FillValue)
EU_plot(:6,:) = EU(variable|:, time|120:395) ; name the dimensions and
reorder easily.
EU_plot(7,:) = dim_avg_n(EU_plot(0:6,:),0)
EUmax := new((/nraw,nmax/),float, EU_plot at _FillValue)
;; rather than having 3 different iterable integers, simplify things with
an array up front.
;;;;
t_lbd = ispan(0, ncol-12, 12) ; lower bounds to find max over.
t_ubd = t_lbd + 11 ; upper bounds to find max over.
do t=0,dimsizes(t_lbd)-1
EUmax(:,t) = dim_max_n(EU_plot(:,t_lbd(t):t_ubd(t)),1) ;; use the array
based functions where possible.
end do
print(EUmax)
On Tue, Sep 29, 2015 at 12:22 PM, Doumbia <thiernodoumbia at yahoo.fr> wrote:
> I add some thing in your code and it gives me the good results.
> yr = i would be yr = i+1.
>
> The new script is:
> do n=0,7
> yr=0
> k =0
> do i = 11,275,12
> EUmax(n,k) = max(EU_plot(n,yr:i))
> k=k+1
> yr=i+1
> end do
> end do
>
> Jack, thank again.
> Thierno
>
> > Le 29 Sep 2015 à 18:02, Doumbia <thiernodoumbia at yahoo.fr> a écrit :
> >
> > Hi Jack,
> > I really appreciate your teaching skills.
> >
> > I recognize that there’s weird things in my script but I apologize for
> that, I am new in NCL.
> >
> > Unfortunately, your suggestions don’t give the good results i.e. the
> maximum of monthly NO2 data for each year. I compared these results with
> those obtained from excel.
> >
> > You are right, the "EU(120:395,0)” is for 1990 to 2012 (23 years).
> >
> > Thank you for your help.
> >
> > Thierno
> >
> >
> >>
> >> ...
> >> “The results I’ve obtained aren’t what I expected.”
> >> ...
> >> Well, even Aristotle would struggle to figure out what you expected if
> you didn't tell him…
> >>
> >> Your script still got visible mistakes though. For example the loop is
> quite extravagant:
> >> …
> >> k = ispan(0,11,1)
> >> do n=0,7
> >> do i = 0,275,12
> >> do j=0,11
> >> EUmax(n,:) = max(EU_plot(n,i+k(j))) <== “j” will always be the same
> type as, and equal to “k(j)”?
> >> end do
> >> end do
> >> end do
> >> …
> >> and since the left side of your equation has a free dimension, the
> variable will always be overwritten up to the end of the loop.
> >>
> >> You can clean the loop and do something like,
> >> do n=0,7
> >> yr=0
> >> k =0
> >> do i = 11,275,12
> >> EUmax(n,k) = max(EU_plot(n,yr:i))
> >> k=k+1
> >> yr=i
> >> end do
> >> end do
> >>
> >> I was also wondering whether from your file “EU(120:395,0)” will give
> you information from 2000 to 2012(12 years)? Probably that is the
> unexpected result you mentioned. Who knows?
> >>
> >> I hope that helps.
> >>
> >> Jack
> >>
> >>> On 29 Sep 2015, at 15:02, Doumbia <thiernodoumbia at yahoo.fr> wrote:
> >>>
> >>> Dear ncl users,
> >>>
> >>> I am trying to compute the monthly maximum NO2 in a yearly basis.
> >>>
> >>> My input file contains 7 columns representing different variables and
> 396 lines (monthly mean NO2 data from 1980 to 2012). I am only interested
> by the 2000-2012 period .
> >>>
> >>> The results I’ve obtained aren’t what I expected.
> >>> <max_of_monthly_data.ncl><Europe_bis_ncl.txt>
> >>> I will appreciate any help to resolve this.
> >>>
> >>> Please find attached my script as well as my input file.
> >>>
> >>> Thank you in advance,
> >>> Thierno
> >>>
> >>> _______________________________________________
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> >
>
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