[ncl-talk] do loop based on variable similar names

[Hoffman Cheung]

Hi Zoey,

In this case, you may just read the values inside the do loop, and delete
the variable at the end of the loop.

izMin = (/.../)
izMax = (/.../)

do i = 1, 13
     iz = ind(field(0,:).ge.izMin(i) .and. field(0,:).lt.izMax(i)) ; define
izMin and izMax explicitly before executing the loop

    if (.not. any(ismissing(iz)) then
        print("Number of data fall between "+ izMin(i) + " and " + izMax(i)
+ " = " + dimsizes(iz))
    else
        print("No data can be found for the values between "+ izMin(i) + "
and " + izMax(i))
    end if

    delete(iz)
end do

Cheers,
Hoffman



2016-11-10 3:44 GMT+01:00 <xyzheng at mail.ustc.edu.cn>:

> Hello,
> I am looking for a way to call a series of variables through  their names
> (string) in NCL.These variables are of different sizes,so they can't be
> set as an array iz(k) of fixed size.  And I don't know how to do loop and some
> other operations based on these similar names since ("iz"+i) can't be
> identified as a variable in the following script.  Can anyone help?
> ............................................................
> .........................................................
>
> fieldf(0,:) = asciiread(fi,-1,"float")
>    iz1=ind(fieldf(0,:).ge.0.and.fieldf(0,:).lt.1.5)
>    iz2=ind(fieldf(0,:).ge.1.and.fieldf(0,:).lt.2.2)
>    iz3=ind(fieldf(0,:).ge.2.2.and.fieldf(0,:).lt.3)
>    iz4=ind(fieldf(0,:).ge.3.and.fieldf(0,:).lt.4.2)
>    iz5=ind(fieldf(0,:).ge.4.2.and.fieldf(0,:).lt.5.6)
>    iz6=ind(fieldf(0,:).ge.5.6.and.fieldf(0,:).lt.6)
>    iz7=ind(fieldf(0,:).ge.6.and.fieldf(0,:).lt.7)
>    iz8=ind(fieldf(0,:).ge.7.and.fieldf(0,:).lt.8)
>    iz9=ind(fieldf(0,:).ge.8.and.fieldf(0,:).lt.9.1)
>    iz10=ind(fieldf(0,:).ge.9.1.and.fieldf(0,:).lt.10)
>    iz11=ind(fieldf(0,:).ge.10.and.fieldf(0,:).lt.11)
>    iz12=ind(fieldf(0,:).ge.11.and.fieldf(0,:).lt.12)
>    iz13=ind(fieldf(0,:).ge.12.and.fieldf(0,:).lt.13)
>
>    do i=1,13
>          print(dimsizes("iz"+i))
>   end do
> ............................................................
> ........................................
>
> Thanks very much,
>
> Zoey
>
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