[ncl-talk] unable to extract data and plot it for a smaller domain.

Rashed Mahmood rashidcomsis at gmail.com
Sat Sep 19 07:17:31 MDT 2020


I would go with Rick's suggestions, have you tried that?

Cheers,
Rashed

On Sat, Sep 19, 2020 at 1:23 PM Geeta Geeta <geetag54 at yahoo.com> wrote:

> Hi Mr Rashed.
> Kindly tell me if you have seen the data and your thoughts on the problem
>
> thanks
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> Geeta.
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>  On Friday, 18 September, 2020, 04:01:26 pm IST, Rashed Mahmood <
> rashidcomsis at gmail.com> wrote:
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>  What is the size of the data? Including ncl-talk here, there is a way to
> upload files, see this: https://www.ncl.ucar.edu/ftp_files.shtml
> Or if not too heavy, you could share it through dropbox or google drive
> etc.
> Cheers,Rashed
>
> On Fri, Sep 18, 2020 at 6:48 AM Geeta Geeta <geetag54 at yahoo.com> wrote:
> Hi Mr Rashed, \How can I send you the data.
> if you share the link I can send the data by ftp or by any other
> means. Geeta.
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>  On Friday, 18 September, 2020, 01:48:36 am IST, Rashed Mahmood <
> rashidcomsis at gmail.com> wrote:
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>  Sorry, without a data file it would be impossible for me to see what is
> going on.
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> On Thu, Sep 17, 2020 at 8:35 PM Geeta Geeta <geetag54 at yahoo.com> wrote:
> Thanks Mr Mahmood.
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> Data file is big, however I am attaching the script.
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> thanks
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> Geeta.
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>  On Thursday, 17 September, 2020, 11:53:16 pm IST, Rashed Mahmood <
> rashidcomsis at gmail.com> wrote:
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>  Hi Geeta,It would be difficult to answer this question without a data
> file and the script used to plot these figures. Is it possible to share
> data and the NCL script?Cheers,Rashed
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>
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> On Thu, Sep 17, 2020 at 8:05 PM Geeta Geeta via ncl-talk <
> ncl-talk at mailman.ucar.edu> wrote:
>
> Hi.
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> This issue was sorted out a few days ago. Now I  am finding a small
> problem which is the shift of the position of the clouds.
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> I mean when I plot the data for regional domain, clouds seem to be shifted
> by about 2 degree compared to the original domain plot (attachments) .
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> Requesting once again to sort out this issue too.
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> Geeta.
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>  On Friday, 11 September, 2020, 10:10:16 pm IST, Dennis Shea <
> shea at ucar.edu> wrote:
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>  Are the latitude and longitudes on the file?
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> 1) If "yes", just read as indicated below.2) If "no",  the projection
> information must be used to generate the latitude and longitude information
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> ------------------------
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> The following functions may be useful when the latitudes and longitudes
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> region_ind
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> getind_latlon2d
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>  f = addfile("3DIMG_23JUN2018_0300_L1C_ASIA_MER.h5" , "r")
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>  glon2d = f->...longitude_variable ...
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>  glat2d = f->...latitude_variable...
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>  printMinMax(glat2d, 0)
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>  printMinMax(glon2d, 0)
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>  latS = 10 ; California [*rough*]
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>  ji = region_ind (glat2d,glon2d, latS, latN, lonW, lonE)
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>  jStrt = ji(0) ; lat start
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>  jLast = ji(1) ; lat last
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>  iStrt = ji(2) ; lon start
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>  iLast = ji(3) ; lon last
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>  LAT2D = glat2d(jStrt:jLast,iStrt:iLast)
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>  LON2D = glon2d(jStrt:jLast,iStrt:iLast)
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>  printMinMax(LAT2D, 0)
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>  printMinMax(LON2D, 0)
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>  ; read data just for the region of interest
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>  x = f->IMG_TIR1(0,jStrt:jLast,iStrt:iLast)
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>  printVarSummary(x)
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>  printMinMax(x)
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> On Fri, Sep 11, 2020 at 8:41 AM Geeta Geeta via ncl-talk <
> ncl-talk at mailman.ucar.edu> wrote:
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> the NxM grid is the larger grid,  of the size 55N and 61E.
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> will it be minI  = 70* 61/(105.5-44.5) ??
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> does not seem to be correct, I am not achieving anything
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> Geeta.
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>  On Friday, 11 September, 2020, 07:48:54 pm IST, Rick Brownrigg <
> brownrig at ucar.edu> wrote:
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>  Hi,
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> No, not in meters -- you're trying to find the indices of the grid cells
> that correspond to the corners of your smaller domain. For instance, what
> are the values i,j that correspond to the corner (-10N,44.5E)
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> On Fri, Sep 11, 2020 at 8:11 AM Geeta Geeta <geetag54 at yahoo.com> wrote:
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> Soory Mr Rick. It is not clear to me.
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> 4 corners of large  domain are  (-10N,44.5E) , (-10,105.5), (45.5,105.5),
> (45.5,44.5).
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> I want small domain to be 10-20N/70-75E.
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> So I have to calculate the X Y (distance in meters)?.
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> kindly clarify .
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>  On Friday, 11 September, 2020, 07:20:57 pm IST, Rick Brownrigg <
> brownrig at ucar.edu> wrote:
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>  Hi,
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> I *think* the trick here is to compute the i,j indices of the grid that
> correspond to your smaller domain. Since it's a mercator projection, and
> the original domain is relatively small (60x60 degs), I would think you
> could get decent results by using a simple linear scaling to find those
> values. So if the grid is NxM (LatxLon), and you extract the min/max
> lat/lons from the attributes into variables minLon, maxLon, etc.,  then
> something like:
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>   minI = tointeger( minLonSmallerDomain * (M -0) / (maxLon - minLon) )  ;
> truncating
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>   maxI = tointeger( maxLonSmallerDomain * (M -0) / (maxLon - minLon)
> )...similarly for Y...
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> and then:
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>  Plot(0)                           =
> gsn_csm_contour_map(wks,TIR1_INVERTED(0,minJ:maxJ,minI:maxI),rescount)
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> and don't forget to substitute appropriate values into the
> mpLeft/RightCornerLat/LonF resources.
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> Does that make sense?
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> Rick
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> On Fri, Sep 11, 2020 at 4:22 AM Geeta Geeta via ncl-talk <
> ncl-talk at mailman.ucar.edu> wrote:
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> Hi.
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> I have satellite data which has a resultion of 4 km (TIR1) and there is projection information provided in the datafile.
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> integer Projection_Information ( DIM_000 )
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>         DIMENSION_LIST :    <ARRAY of 0 elements>
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>         false_easting :      0
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>         false_northing :      0
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>         grid_mapping_name :    mercatorpor Brightness Temperaturerature
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>         longitude_of_projection_origin :      75
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>         lower_left_lat_lon(degrees) :    (  -10, 44.5 )
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>         lower_right_lat_lon(degrees) :    (  -10, 105.5 )
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>         semi_major_axis :    6378137
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>         semi_minor_axis :    6356752.3142
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>         standard_parallel :    17.75
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>         upper_left_lat_lon(degrees) :    ( 45.5, 44.5 )
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>         upper_left_xy(meters) :    ( -3234623.003937, 5401854.420193 )
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>         upper_right_lat_lon(degrees) :    ( 45.5, 105.5 )
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> The lat/lon are not provided.
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> Plotting the TIR1 (count), radiance and Brightness temperature for the entire domain is happening by using information from the Projection info.
> This INFO is used from the Line numbers 109-114 of the code.
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> My questions are 1. I am Not able to plot the data for a smaller domain of
> my ineterst
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>                           2. since I am unable to attch the lat/lon arrays to the variables, I am unable to plot the data for a smaller domain and unable to write the data for a smaller domain of my intererst.
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> the Images are attached.
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> Request someone to help me.
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> Geeta._______________________________________________
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