<div dir="ltr">Hi Andreas,<div>Based on that snippet of code the only line I see where you may be dividing by zero is this line:</div><div><i style="font-size:12.8px">test_rc_nies = regline_stats(ntimes3,value_<wbr>test_nies({i:j}))</i><br></div><div><i style="font-size:12.8px"><br></i></div><div><span style="font-size:12.8px">Following through your do loops you will have iterations when both input arrays are of size 1 (when say i <i>and</i> j = 1989).</span></div><div><span style="font-size:12.8px"><br></span></div><div><span style="font-size:12.8px">Quick testing here shows that each of the input arrays need to be of size 3 or greater to avoid triggering that error message of dividing by 0. To avoid this situation you can change your code to this to make sure more than 2 values are input into regline_stats:</span></div><div><span style="font-size:12.8px"><br></span></div><div><span style="font-size:12.8px">if (j-i.ge.2) then</span></div><div><div style="font-size:12.8px"><i> test_rc_nies = regline_stats(ntimes3,value_<wbr>test_nies({i:j}))</i></div><div style="font-size:12.8px"><i> if (j-i .ge. 9) then<br> finarr_nies({i},{j},0) = where(test_rc_nies@b(1) .gt. 0 .and. test_rc_nies@b95(0) .gt. 0 , finarr_nies({i},{j},0), value_test@_FillValue )<br> else <br> finarr_nies({i},{j},0) = where(test_rc_nies@b(1) .lt. 0 .and. test_rc_nies@b95(1) .lt. 0 , finarr_nies({i},{j},0), value_test@_FillValue ) <br> end if</i></div></div><div><span style="font-size:12.8px">end if</span></div><div><span style="font-size:12.8px"><br></span></div><div><span style="font-size:12.8px">Hope that helps. If not, or if you have further questions please respond to ncl-talk...</span></div><div><span style="font-size:12.8px">Adam</span></div></div><div class="gmail_extra"><br><div class="gmail_quote">On Wed, Jun 7, 2017 at 1:16 PM, Andreas Chrysanthou <span dir="ltr"><<a href="mailto:eeac@leeds.ac.uk" target="_blank">eeac@leeds.ac.uk</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
<div style="word-wrap:break-word">
<div>Following up on the loop I created, when I tried to add some criteria based on the slope of the linear trend and the regression coefficients in order to save them to a new array I got the error:
</div>
<div><br>
</div>
<div><i>fatal:divide: Division by 0, Can't continue<br>
fatal:Div: operator failed, can't continue</i></div>
<div><br>
</div>
<div>I want to store the calculated value only when it meets one of the following criteria.</div>
<div>Any ideas on how to improve the syntax? Or ways to bypass the problem?</div>
<div><br>
</div>
<div>I’ve read on the NCL website in the lazy evaluation section that: "If the left operand is an array, you cannot depend on a left-hand side test to guard against possible error conditions resulting from evaluating an expression on the right side.
For example, you cannot avoid division by 0 and the consequences of an error result…”</div>
<div><br>
</div>
<div>The snippet of the code is:</div>
<div><br>
</div>
<div>
<div><i>finarr_nies = new((/22,22,1/),typeof(value_<wbr>test))</i></div>
<div><i>finarr_nies!0 = "startyear"</i></div>
<div><i>finarr_nies&startyear = ispan(1980,2001,1)</i></div>
<div><i>finarr_nies!1 = "endyear"</i></div>
<div><i>finarr_nies&endyear = ispan(1989,2010,1)</i></div>
</div>
<div><i><br>
</i></div>
<div><i>do i=1980,2001,1<br>
do j=1989,2010,1<br>
ntimes3 = ispan(i,j,1)<br>
start_date = i<br>
end_date = j<br>
test_rc_nies = regline_stats(ntimes3,value_<wbr>test_nies({i:j}))</i></div>
<div><i> if (j-i .ge. 9) then<br>
finarr_nies({i},{j},0) = where(test_rc_nies@b(1) .gt. 0 .and. test_rc_nies@b95(0) .gt. 0 , finarr_nies({i},{j},0), value_test@_FillValue )<br>
else <br>
finarr_nies({i},{j},0) = where(test_rc_nies@b(1) .lt. 0 .and. test_rc_nies@b95(1) .lt. 0 , finarr_nies({i},{j},0), value_test@_FillValue ) <br>
end if<br>
delete(ntimes3)<br>
end do<br>
end do</i></div>
<div><br>
</div>
<div><br>
</div>
Cheers,
<div>Andreas<br>
<div>
<blockquote type="cite">
<div>On 6 Jun 2017, at 13:22, Andreas Chrysanthou <<a href="mailto:eeac@leeds.ac.uk" target="_blank">eeac@leeds.ac.uk</a>> wrote:</div>
<br class="m_-3107102158327613671Apple-interchange-newline">
<div>
<div style="word-wrap:break-word">
<div>
<div style="letter-spacing:normal;text-align:start;text-indent:0px;text-transform:none;white-space:normal;word-spacing:0px;word-wrap:break-word">
<div style="letter-spacing:normal;text-align:start;text-indent:0px;text-transform:none;white-space:normal;word-spacing:0px;word-wrap:break-word">
<div style="letter-spacing:normal;text-align:start;text-indent:0px;text-transform:none;white-space:normal;word-spacing:0px;word-wrap:break-word">
<div style="letter-spacing:normal;text-align:start;text-indent:0px;text-transform:none;white-space:normal;word-spacing:0px;word-wrap:break-word">
<div style="letter-spacing:normal;text-align:start;text-indent:0px;text-transform:none;white-space:normal;word-spacing:0px;word-wrap:break-word">
<div>I really appreciate your help Adam and Dennis.</div>
<div><br>
</div>
<div>I could manage to extract the one value I wanted from the slope and the regression coefficients, pass it on to the new array outside of the loop and improved the code by writing the loop with variables instead of constants.</div>
<div><br>
</div>
<div>Thanks so much.</div>
<div><br>
</div>
<div><br>
</div>
<div></div>
</div>
</div>
</div>
</div>
</div>
</div>
<br>
<div>
<blockquote type="cite">
<div>On 6 Jun 2017, at 01:29, Dennis Shea <<a href="mailto:shea@ucar.edu" target="_blank">shea@ucar.edu</a>> wrote:</div>
<br class="m_-3107102158327613671Apple-interchange-newline">
<div>
<div dir="ltr">
<div>
<div>I am not sure what is meant by: "There was one not insignificant thing I didn’t mention"<br>
<br>
---<br>
</div>
As you note:<br>
<br>
"the regline_stats function for the b calculates both the b(0) +b(1*)x of the linear regression, while the b95 calculates both the 2.5% and 97.5% regression coefficient confidence intervals. So when it tries to save to that cell, there are two values for the
@b and @b95."<br>
<br>
</div>
Change: <br>
<div>
<div>
<div><font size="3" face="Calibri, Arial, Helvetica, sans-serif"> trend_slope=test_rc@b*10 ; prints slope of the linear trend for the selected range of years</font></div>
<div><font size="3" face="Calibri, Arial, Helvetica, sans-serif"> reg_coeff=test_rc@b95 ; prints 2.5% and 97.5% regression coefficient confidence intervals
<br>
<br>
</font></div>
<div><font size="3" face="Calibri, Arial, Helvetica, sans-serif">To extract only one value<br>
</font></div>
<div><font size="3" face="Calibri, Arial, Helvetica, sans-serif"> trend_slope=test_rc@b(1) *10 ; prints slope of the linear trend for the selected range of years</font></div>
<font size="3" face="Calibri, Arial, Helvetica, sans-serif"> reg_coeff=test_rc@b95(1) ; prints 2.5% and 97.5% regression coefficient confidence intervals
<br>
<br>
---<br>
<br>
"</font>4 different columns (start_date, end_date,trend_slope,reg_coeff<wbr>)<br>
<br>
---<br>
</div>
<div>The following create 4 (well 3) different columns. I may give you an idea how to proceed.
<br>
</div>
<div>Also, good programming practice is to use variables and not constants.<br>
</div>
<div><br>
nyrSpan = 10<br>
nyrCrit = 10<br>
nyrStrt1 = 1980<br>
nyrStrt2 = 2001<br>
nyrLast1 = nyrStrt1+nyrSpan-1<br>
nyrLast2 = 2010<br>
<br>
NTIM = 1000 ; arbitrary max possible # elements<br>
strtYear = new( NTIM, "integer")<br>
lastYear = new( NTIM, "integer")<br>
trend = new( NTIM, "float")<br>
rc = new( NTIM, "float")<br>
<br>
nt = -1<br>
do nyrStrt=nyrStrt1,nyrStrt2<br>
do nyrLast=nyrLast1,nyrLast2<br>
nyrs = nyrLast-nyrStrt+1<br>
if (nyrs.ge.nyrCrit) then<br>
test_rc = regline_stats(tofloat(ispan(1,<wbr>nyrSpan,1)),random_normal(-1,<wbr>1,nyrSpan))<br>
nt = nt+1<br>
strtYear(nt) = nyrStrt<br>
lastYear(nt) = nyrLast<br>
spanYear = nyrLast-nyrStrt+1<br>
rc(nt) = (/ test_rc /) ; (/.../) no meta data ; same as b(1)<br>
;trend(nt) = ?????<br>
print(strtYear(nt)+" "+lastYear(nt)+" "+spanYear+" "+rc(nt))<br>
end if<br>
end do<br>
end do<br>
<br>
print("======================<wbr>===========================")<br>
ntim = nt+1 ; # of elements<br>
print("ntim="+ntim)<br>
<br>
</div>
<div><br>
</div>
</div>
</div>
<div class="gmail_extra"><br>
<div class="gmail_quote">On Mon, Jun 5, 2017 at 11:10 AM, Andreas Chrysanthou <span dir="ltr">
<<a href="mailto:eeac@leeds.ac.uk" target="_blank">eeac@leeds.ac.uk</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
<div style="word-wrap:break-word">There was one not insignificant thing I didn’t mention.
<div><br>
</div>
<div>the regline_stats function for the b calculates both the b(0) +b(1*)x of the linear regression, while the b95 calculates both the 2.5% and 97.5% regression coefficient confidence intervals.</div>
<div>So when it tries to save to that cell, there are two values for the @b and @b95. </div>
<div><br>
</div>
<div>That’s why I got the error of : "fatal:Dimension sizes on right hand side of assignment do not match dimension sizes of left hand side"</div>
<div><br>
</div>
<div>I only want the slope of the liner trend (b(1)) and my criterion if I need to save these values is that the confidence intervals should not be negative (that would probably need to be included in the if loop). </div>
<div>But I don’t know how to keep only one value of those pair of calculated stats.</div>
<div><br>
</div>
<div>Cheers,</div>
<div>Andreas</div>
<div>
<div class="m_-3107102158327613671h5">
<div><br>
</div>
<div><br>
</div>
<div>
<div>
<blockquote type="cite">
<div>On 5 Jun 2017, at 17:17, Adam Phillips <<a href="mailto:asphilli@ucar.edu" target="_blank">asphilli@ucar.edu</a>> wrote:</div>
<br class="m_-3107102158327613671m_-1930109600680038890Apple-interchange-newline">
<div>
<div dir="ltr"><font face="arial, helvetica, sans-serif">Hi Andreas,</font>
<div><font face="arial, helvetica, sans-serif">As there are singular values for reg_coef and trend_slope for each start and end time, I think it would be best to simply create a 3D array dimensioned (start_date, end_date,2), with the last
dimension (0) = trend_slope and (1) representing reg_coeff. If you <i>must</i> have a 4-dimensional array then you should create an array that is dimensioned 22 x 22 x 2 x 2, but (:,:,1,0) and (:,:,0,1) will be missing. In the example below I show
how to create both types of arrays:</font></div>
<div><font face="arial, helvetica, sans-serif"><br>
</font></div>
<div><font face="arial, helvetica, sans-serif">finarr = new((/22,22,2/),typeof(value_t<wbr>est))</font></div>
<div><font face="arial, helvetica, sans-serif">finarr!0 = "startyear"</font></div>
<div><font face="arial, helvetica, sans-serif">finarr&startyear = ispan(1980,2001,1)</font></div>
<div><font face="arial, helvetica, sans-serif">finarr!1 = "endyear"</font></div>
<div><font face="arial, helvetica, sans-serif">finarr&endyear = ispan(1989,2010,1)</font></div>
<div>
<div><font face="arial, helvetica, sans-serif">finarrZ = new((/22,22,2,2/),</font><span style="font-family:arial,helvetica,sans-serif">typeof(value<wbr>_test))</span></div>
<div><font face="arial, helvetica, sans-serif">finarrZ!0 = "startyear"</font></div>
<div><font face="arial, helvetica, sans-serif">finarrZ&startyear = ispan(1980,2001,1)</font></div>
<div><font face="arial, helvetica, sans-serif">finarrZ!1 = "endyear"</font></div>
<div><font face="arial, helvetica, sans-serif">finarrZ&endyear = ispan(1989,2010,1)</font></div>
<div><font face="arial, helvetica, sans-serif"><br>
</font></div>
<div><font face="arial, helvetica, sans-serif">do i=1980,2001,1</font></div>
<div><font face="arial, helvetica, sans-serif"> do j=1989,2010,1</font></div>
<div><font face="arial, helvetica, sans-serif"> ntimes=ispan(i,j,1)</font></div>
<div><font face="arial, helvetica, sans-serif"> if (j-i .ge. 9 ) then</font></div>
<div><font face="arial, helvetica, sans-serif"> test_rc=regline_stats(ntimes,<wbr>value_test({i:j}))</font></div>
<div><font face="arial, helvetica, sans-serif"> print(test_rc)</font></div>
<div><font face="arial, helvetica, sans-serif"> start_date=i</font></div>
<div><font face="arial, helvetica, sans-serif"> end_date=j</font></div>
<div><font face="arial, helvetica, sans-serif"> finarr({i},{j},0) = test_rc@b*10 ; prints slope of the linear trend for the selected range of years</font></div>
<div><font face="arial, helvetica, sans-serif"> finarr({i},{j},1) = test_rc@b95 ; prints 2.5% and 97.5% regression coefficient confidence intervals </font></div>
<div><font face="arial, helvetica, sans-serif"> finarrZ(</font><span style="font-family:arial,helvetica,sans-serif">{i},{j},0,0) = test_rc@b*10</span><span style="font-family:arial,helvetica,sans-serif"> </span></div>
<div><span style="font-family:arial,helvetica,sans-serif">
</span><font face="arial, helvetica, sans-serif"> finarrZ(</font><span style="font-family:arial,helvetica,sans-serif">{i},{j},1,1) = </span><span style="font-family:arial,helvetica,sans-serif">test_rc@b95 </span></div>
<div><font face="arial, helvetica, sans-serif"> else </font></div>
<div><font face="arial, helvetica, sans-serif"> print(“this age range has not been selected, since its less than 9 years")</font></div>
<div><font face="arial, helvetica, sans-serif"> end if </font></div>
<div><font face="arial, helvetica, sans-serif"> delete(ntimes)</font></div>
<div><font face="arial, helvetica, sans-serif"> end do</font></div>
<div><font face="arial, helvetica, sans-serif">end do </font></div>
</div>
<div><br>
</div>
<div>Hope that helps. If you have any further questions please respond to the ncl-talk email list.</div>
<div>Adam</div>
<div><br>
</div>
</div>
<div class="gmail_extra"><br>
<div class="gmail_quote">On Mon, Jun 5, 2017 at 9:48 AM, Andreas Chrysanthou <span dir="ltr">
<<a href="mailto:eeac@leeds.ac.uk" target="_blank">eeac@leeds.ac.uk</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
<div style="word-wrap:break-word">
<div id="m_-3107102158327613671m_-1930109600680038890m_5767769911056133050divtagdefaultwrapper" dir="ltr">
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
Hi NCL users,</p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
<br>
</p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
I created a loop for calculating a linear trend sensitivity for different start and end dates. </p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
My timeseries span over 1980-2010 and I want to calculate the linear trend of the timeseries for when the start - end date are more than >= 9years.
<br>
</p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
(1980-1989, 1980-1990, 1980-1991,..., 1980-2010</p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
1981-1990, 1981-1991, ..., 1981-2010</p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
...</p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
...</p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
...</p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
2000-2009, 2001-2010<br>
</p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
2001-2010)</p>
<div><br>
</div>
<div><br>
</div>
<div>
<div style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
I’ve created the loops that calculate those values but I need to save them in an array as 4 different columns (start_date, end_date,trend_slope,reg_coeff<wbr>)</div>
<div style="margin-top:0px;margin-bottom:0px;font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
<span style="font-size:12pt">My aim is to plot those as a a contour box plot with x axis the start date and y axis the end date, and the calculated (i’m gonna filter out those values with some criteria) trend values based on a colormap.</span></div>
</div>
<div style="margin-top:0px;margin-bottom:0px;font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
<span style="font-size:12pt"><br>
</span></div>
<div style="margin-top:0px;margin-bottom:0px"><font size="3" face="Calibri, Arial, Helvetica, sans-serif">Can you help me in order to save the values to that new array so I can plot it?</font></div>
<div style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
<br>
</div>
<div style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
A snippet of the code follows:</div>
<div style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
<br>
</div>
<div>
<div><span style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:inherit">do i=1980,2001,1</span></div>
<div><font size="3" face="Calibri, Arial, Helvetica, sans-serif"> </font><span style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:inherit">do j=1989,2010,1</span></div>
<div><span style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:inherit"> ntimes=ispan(i,j,1)</span></div>
<div><span style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:inherit">if (j-i .ge. 9 ) then</span></div>
<div><font size="3" face="Calibri, Arial, Helvetica, sans-serif">
</font><span style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:inherit"> test_rc=regline_stats(ntimes,v<wbr>alue_test({i:j}))</span></div>
<div><font size="3" face="Calibri, Arial, Helvetica, sans-serif"> print(test_rc)</font></div>
<div><font size="3" face="Calibri, Arial, Helvetica, sans-serif"> start_date=i</font></div>
<div><font size="3" face="Calibri, Arial, Helvetica, sans-serif"> end_date=j</font></div>
<div><font size="3" face="Calibri, Arial, Helvetica, sans-serif"> trend_slope=test_rc@b*10 ; prints slope of the linear trend for the selected range of years</font></div>
<div><font size="3" face="Calibri, Arial, Helvetica, sans-serif"> reg_coeff=test_rc@b95 ; prints 2.5% and 97.5% regression coefficient confidence intervals </font></div>
<div><font size="3" face="Calibri, Arial, Helvetica, sans-serif">else print(“this age range has not been selected, since its less than 9 years")</font></div>
<div><font size="3" face="Calibri, Arial, Helvetica, sans-serif"> end if </font></div>
<div><font size="3" face="Calibri, Arial, Helvetica, sans-serif"> delete(ntimes)</font></div>
<div><span style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:inherit">end do</span></div>
<div><span style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:inherit">end do </span></div>
</div>
<div style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
<br>
</div>
<div style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
Cheers,</div>
<div style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
Andreas</div>
<span class="m_-3107102158327613671m_-1930109600680038890HOEnZb"><font color="#888888">
<div style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
<br>
</div>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
<br>
</p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
<br>
</p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
<br>
</p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
<br>
</p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
<br>
</p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
<br>
</p>
<p style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
<br>
</p>
<div id="m_-3107102158327613671m_-1930109600680038890m_5767769911056133050Signature" style="font-family:Calibri,Arial,Helvetica,sans-serif;font-size:12pt">
<div id="m_-3107102158327613671m_-1930109600680038890m_5767769911056133050divtagdefaultwrapper" dir="ltr" style="font-size:12pt;font-family:Calibri,Arial,Helvetica,sans-serif">
<font size="1" face="HelveticaNeue-Light"><span style="font-size:13px;font-weight:normal;text-transform:none">
<div>
<div style="white-space:normal">
<div style="white-space:normal">
<div style="white-space:normal">
<div style="white-space:normal">
<div>Andreas</div>
<br>
</div>
</div>
</div>
</div>
</div>
</span></font>
<p><br>
</p>
</div>
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<br></blockquote></div><br><br clear="all"><div><br></div>-- <br><div class="gmail_signature" data-smartmail="gmail_signature"><div dir="ltr"><div><div dir="ltr"><div><div dir="ltr"><div><div dir="ltr"><div><div><div><span><font color="#888888">Adam Phillips <br></font></span></div><span><font color="#888888">Associate Scientist, </font></span><span><font color="#888888">Climate and Global Dynamics Laboratory, NCAR<br></font></span></div></div><div><span><font color="#888888"><a href="http://www.cgd.ucar.edu/staff/asphilli/" target="_blank">www.cgd.ucar.edu/staff/asphilli/</a> </font></span><span><font color="#888888">303-497-1726 </font></span></div><span><font color="#888888"></font></span><div><div><span><font color="#888888"><br></font></span><div><span><font color="#888888"><a href="http://www.cgd.ucar.edu/staff/asphilli" target="_blank"></a></font></span></div></div></div></div></div></div></div></div></div></div></div>
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