<div dir="ltr"><div><div><div><div><div><div>[1] Yes ... there is a way<br></div>[2] But ... why would ypu want to do that? It introduces a 'spectral gap' in the time series.<br><br>===<br></div> foo(time,lat,lon)<br><br></div> time has units understood by cd_calendar<br> <a href="https://www.ncl.ucar.edu/Document/Functions/Built-in/cd_calendar.shtml">https://www.ncl.ucar.edu/Document/Functions/Built-in/cd_calendar.shtml</a><br><br></div><div> TIME = cd_calendar(time, 0)<br></div><div><br></div> ikeep = ind(.not.(TIME(:,1).eq.3 .and. TIME(:,2).eq.31) )<br></div> FOO = foo(ikeep,:,:)<br></div> delete(foo)<br><div><div><div><br> <br></div></div></div></div><div class="gmail_extra"><br><div class="gmail_quote">On Thu, Apr 16, 2015 at 4:16 PM, Xi Chang <span dir="ltr"><<a href="mailto:xi.chang01@gmail.com" target="_blank">xi.chang01@gmail.com</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">Hi NCL, <div>I have 40 years daily data, i need to delete 31 march only for the leap year, is there any quick way to do that?</div><div><br></div><div>Regards</div>
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